(09 Oct 2020) – Mathematical Reasoning, 2nd Shift NTA UGC NET JRF Question paper, Answer key

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1. In an examination it is required to get 36% of maximum marks to pass. A student got 90 marks and was declared a failure with 9 marks. Calculate maximum marks.

(1) 200
(2) 275
(3) 300
(4) 225
एक परीक्षा में उत्तीर्ण होने के लिए अधिकतम अंक का 36 प्रतिशत प्राप्त करना आवश्यक है। एक छात्र को 90 अंक मिले और उसे 9 अंकों के साथ अनुत्तीर्ण घोषित कर दिया गया। अधिकतम अंकों की गणना करें।

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  Answer 2
Explanation: 99×100/36
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2. If 5472 ➜ 9, 6342 ➜ 6, and 9237 ➜ P, then P is : (➜ means implies)

(a) 2
(b) 3
(c) 4
(d) 5

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  Answer 2
Explanation: Add all digits 9+2+3+7= 2+1=3
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3. The next two terms of the progression as 60, 30, 20, 15 are:

(1) 10 and 5
(2) 4 and 2
(3) 10 and 8
(4) 12 and 10

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  Answer 4
Explanation: 30 is 1/2 of 60.; 20 is 2/3 of 30.
15 is 3/4 of 20.; 12 is 4/5 of 15.
10 is 5/6 of 12.
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4. The simple interest on a certain sum of money for 2 years at the rate of 6% per annum comes to 300. The compound interest at the same rate, for the same time and on the same sum of money would be:

(1) 310
(2) 308
(3) 307
(4) 309
एक निश्चित राशि पर 2 वर्ष के लिए 6% प्रति वर्ष की दर से साधारण ब्याज 300 आता है। समान दर पर, समान समय के लिए और समान राशि पर चक्रवृद्धि ब्याज होगा:

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  Answer 4
Explanation: 150/6 x 100= 2500 Principal
Successive of 6% for compound interest
= 6+6+(36/100)= 12.36
2500 x 12.36%= 308.75
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5. A shopkeeper sells an item at a discount of 40% on the item’s listed price of Rs. 1500.00. He still makes a profit of 20% on the original cost of the item. What is the original cost of the item?

(1) Rs. 500
(2) Rs. 750
(3) Rs. 600
(4) Rs. 1080
एक दुकानदार एक वस्तु को वस्तु के सूचीबद्ध मूल्य पर 40% की छूट पर बेचता है। 1500 वह अभी भी वस्तु की मूल लागत पर 20% का लाभ कमाता है। वस्तु की मूल लागत क्या है?

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  Answer 2
Explanation: 1500 x 60% = 900
900/120 x 100= 750
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6. A person in a car drives along a straight road from point A to point B at a speed of 60 km/hour for 15 minutes and then from point B to point C at a speed of 90 km/hour for 10 minutes. The average speed of his travel from point A to C is:

A 75 km/hr
B 72 km/hr
C 68 km/hr
D 78 km/hr
एक कार में एक व्यक्ति एक सीधी सड़क पर बिंदु A से बिंदु B तक 60 किमी/घंटा की गति से 15 मिनट और फिर बिंदु B से बिंदु C तक 90 किमी/घंटा की गति से 10 मिनट तक ड्राइव करता है। बिंदु A से C तक उसकी यात्रा की औसत गति है:

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  Answer 2
Explanation: 2S1*S2/S1 + S
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7. A student scores 55, 60, 65 and 70 respectively in english, physics, chemistry and mathematics. If the credits are assigned to english, physics, chemistry and mathematics are 2, 3, 3 and 4 respectively, then what would be the average mark of the student?

A 62.50
B 63.75
C 64.25
D 64.75
एक छात्र अंग्रेजी, भौतिकी, रसायन विज्ञान और गणित में क्रमशः 55, 60, 65 और 70 अंक प्राप्त करता है। यदि अंग्रेजी, भौतिकी, रसायन विज्ञान और गणित को क्रमशः 2, 3, 3 और 4 क्रेडिट दिए गए हैं, तो छात्र का औसत अंक क्या होगा?

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  Answer 2
Explanation: Weighted average:
55 x 2/12 = 9.16
60 x 3/12 = 15
65 x 3/12 = 16.25
70 x 4/12 = 23.33
Total = 63.75
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8. A clock takes 5 seconds to strike 5 times at 5 O’clock. How long will it take to strike 9 times at 9 o’clock?

A 9 seconds
B 12 seconds
C 10 seconds
D 8 seconds

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  Answer 3
Explanation: 5 Stike → 4 intervals = 5seconds
9 Stike → 8 intervals = 10seconds
Or a b c d e
count 4 time intervals, so each interval
is 5/4 sec long
At 9 o’clock, there will be 8 time intervals,
and each one is 5/4 sec long, so it
takes 5/4% X 8+= 10 sec to strike 9 o’clock
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9. The average of 70 numbers is 32. If each number is increased by 3, then the new average will become:

A 31
B 35
C 33
D 37

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  Answer 2
Explanation: Mean property average vary in same proportion = 32+3=35
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10. Find odd one out in from the following: 5, 7, 12, 17, 19, 23

A 7
B 17
C 12
D 19

SHOW ANSWER
  Answer 3
Explanation: All other numbers are prime numbers except 12.
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4 thoughts on “(09 Oct 2020) – Mathematical Reasoning, 2nd Shift NTA UGC NET JRF Question paper, Answer key”

  1. 9/10
    Thank you mam
    Mere shift ka ye ques the math glt hue the pr aapke solution se ab shi ho gya mam aur aapke book se pratice krti huu😊
    Dream believe act achieve😍
    Navlearner##navclasses##jrf is mine

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