01 Oct 2020 – Data Interpretation, 1st & 2nd Shift NTA UGC NET JRF Question paper, Answer key

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(1-5) The table below embodies data on the number of students who appeared (A) and passed (P) in a competitive examination from four different zones (K L M and N) during the year 2014 to 2019.

1. The total number of students who passed from Zone-M in all the six years taken together is approximately what percentage of the total number of students who appeared from Zone-M in all the six years taken together?


1. 56%
2.58%
3. 60%
4. 64%
एक साथ सभी छह वर्षों में जोन-एम से उत्तीर्ण छात्रों की कुल संख्या, सभी छह वर्षों में जोन-एम से उपस्थित होने वाले छात्रों की कुल संख्या का लगभग कितना प्रतिशत है?

SHOW ANSWER   Answer 3
Explanation: 2564/4275 x 100 = 59.97
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2. For which of the following zones is the percentage of students who passed out to the total of those who appeared in the examination the minimum in the year 2019?


1. K
2. L
3. M
4. N
निम्नलिखित में से किस क्षेत्र के लिए वर्ष 2019 में परीक्षा में सम्मिलित होने वालों की कुल संख्या में उत्तीर्ण होने वाले छात्रों का प्रतिशत न्यूनतम है?

SHOW ANSWER   Answer 2
Explanation: By observation
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3. What is the ratio of the number of students who passed from Zone-K in the year 2017 compared to that in 2018?


1. 7:5
2. 3:5
3. 5:7
4. 5:3
2018 की तुलना में वर्ष 2017 में जोन-के से उत्तीर्ण छात्रों की संख्या का अनुपात कितना है?

SHOW ANSWER   Answer 3
Explanation: 360/ 504
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4. What is the average number of students who passed in the exam from all the four Zones in the year 2015?


1. 528
2. 529
3. 530
4. 531
वर्ष 2015 में सभी चार क्षेत्रों से परीक्षा में उत्तीर्ण होने वाले छात्रों की औसत संख्या कितनी है?

SHOW ANSWER   Answer 2
Explanation: 2116/4
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5. What is the difference between the total number of students who appeared in the exam and the total number of students who passed in the exam from zone-K in all the six years taken together?


1. 2060
2. 2070
3. 2080
4. 2090
परीक्षा में बैठने वाले छात्रों की कुल संख्या और सभी छह वर्षों में मिलाकर जोन-के से परीक्षा में उत्तीर्ण होने वाले छात्रों की कुल संख्या के बीच का अंतर कितना है?

SHOW ANSWER   Answer 4
Explanation: Appeared in K= 4730
Passes in K= 2640
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(6-10)Consider the following table that presents the results of a competitive MCQ examination, where candidates were tested in their knowledge of physics, chemistry, mathematics and computer science. The table contains the data on the number of candidates securing marks within the specified range of marks. For example, [81-100] specifies the range of marks as ≥81 and ≤100. Marks-wise distribution of candidates:

Subject Total Marks [81-100] [71-80] [61-70] [51-60]
Physics 100 0 1 4 85
Chemistry 100 2 5 875 3350
Maths 100 0 0 0 6
Computer science 50 0 0 0 0
Subject [41-50] [31-40] [21-30] [11-20] [0-10]
Physics 730 4205 10885 9170 1920
Chemistry 6775 7778 5065 1800 1350
Maths 199 3400 15045 6975 1375
Computer science 220 2145 10140 11858 2637

6. What is the ratio of the total number of candidates who scored more than 50 marks in physics to those who scored more than 40 marks in mathematics?


1. 17:49
2. 18:41
3. 43:61
4. 85:199
भौतिकी में 50 से अधिक अंक प्राप्त करने वाले उम्मीदवारों की कुल संख्या का गणित में 40 से अधिक अंक प्राप्त करने वालों से अनुपात कितना है?

SHOW ANSWER   Answer 2
Explanation: 90: 205
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7. If securing over 40% marks is the qualifying criteria for each subject, then the ratio of the number of candidates who qualify in Mathematics compared to those who qualify in computer science is:


1. 15:42
2. 1:2
3. 56:1
4. 1:61
यदि प्रत्येक विषय के लिए योग्यता मानदंड 40% से अधिक अंक प्राप्त करना है, तो कंप्यूटर में उत्तीर्ण उम्मीदवारों की तुलना में गणित में उत्तीर्ण उम्मीदवारों की संख्या का अनुपात विज्ञान है:

SHOW ANSWER   Answer
Explanation: Math: 199 + 6
Comp sci.=40% of 50 = 20 marks= 10140 + 2145+220
= 205:12505
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8. If securing over 60% marks is the qualifying criteria for the subject of Computer science, then what is the approximate percentage of qualified candidates in the subject of computer science (assume no absentees)?


1. 12.65%
2. 8.76%
3. 8.65%
4.0%
Hindi google translated

SHOW ANSWER   Answer 2
Explanation: 2365/27000
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9. Assuming that there are no absentees, what is the total number of candidates who appeared for the examination?


1. More than 50000
2. 25635
3. 26973
4. 27000
यह मानते हुए कि कोई अनुपस्थित नहीं है, परीक्षा में बैठने वाले उम्मीदवारों की कुल संख्या कितनी है?

SHOW ANSWER   Answer
Explanation: If we total, any subject will get 27000 as all candidates appeared for all subjects.
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10. If securing over 60% marks is the qualifying criteria for each of the three subjects of Physics, Chemistry and Mathematics, then the number of candidates who have qualified in all three subjects is:


1. 0
2. 90
3. 6
4. 5
यदि 60% से अधिक अंक हासिल करना भौतिकी, रसायन विज्ञान और गणित के तीनों विषयों में से प्रत्येक के लिए योग्यता मानदंड है, तो तीनों विषयों में उत्तीर्ण होने वाले उम्मीदवारों की संख्या है:

SHOW ANSWER   Answer 1
Explanation: In maths 0 Qualify over 60%
So no one qualified in all three subjects.
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6 thoughts on “01 Oct 2020 – Data Interpretation, 1st & 2nd Shift NTA UGC NET JRF Question paper, Answer key”

  1. 10 /10 marks
    Mam ya DI Maine Subah morning me hi solve kiye the…… thank you so much man Dobara se Di ko revise karvane Ke Liye #navclasses #navlearner #dbaa #jrfismine

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