(29 Sep – 30 Sep 2020) – Logical Reasoning, 2nd & 1st Shift NTA UGC NET JRF Question paper, Answer key

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1. Wherever there is smoke, there is fire.
There is smoke in Mr Verma’s chamber.
There must be fire in Mr Verma’s chamber.

In accordance with Indian logic, this is an example of:

1. Pratyaksha pramana (Perception)
2. Upmana (Comparison)
3. Hetvabhasa (Fallacy)
4. Vyapti (Invariable relations)
जहां धुंआ है, वहीं आग है।
श्री वर्मा के कक्ष में धुंआ है।
श्री वर्मा के कक्ष में आग होनी चाहिए।
भारतीय तर्क के अनुसार, यह इसका एक उदाहरण है:

SHOW ANSWER
  Answer 3
Explanation: It is a fallacy because smoke can be because of some other reason like smoking or Agarbatti or something else.
There are chances of mistakes, hence fallacy.
©navclasses




2. In the series B, D, H, J, N, P, … What will come after P?


1. U
2. S
3. R
4. T

SHOW ANSWER
  Answer 4
Explanation: +1 +3 ©navclasses




3. In order to authenticate the environmental values as advocated by our ancestors, a scholar cites examples from Vedas. The means of knowledge used by him/her in terms of Indian logic will be called:


1. Anumana (inference)
2. Arthapatti Implication)
3. Shabda (Verbal testimony)
4. Upamana (Comparison)
हमारे पूर्वजों द्वारा बताए गए पर्यावरणीय मूल्यों को प्रमाणित करने के लिए, एक विद्वान वेदों से उदाहरण देता है। भारतीय तर्क के संदर्भ में उनके द्वारा प्रयोग किए गए ज्ञान के साधन कहलाएंगे:

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  Answer 3
Explanation: Śabda means relying on words and testimony of past or present reliable experts. Here also advocated by our ancestors, a scholar cites examples from Vedas is Śabda. ©navclasses




4. If LIGHT is written as GILTH and FIGHT is written as GIFTH, then SIGHT will be written as:


1. GISHT
2. GISTH
3. GSITH
4. GSIHT
यदि LIGHT को GILTH और FIGHT को GIFTH लिखा जाता है, तो SIGHT को इस प्रकार लिखा जाएगा:

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  Answer 2
Explanation: First three interchanged in cross and middle one straight.
Last two interchanged in cross.
©navclasses




5. All flowers are toys. Some toys are trees. Some butterflies are trees, then

A. No butterfly is a flower.
B. Some butterflies are toys.
C. Some toys are flowers.
D. Some trees are flowers.
E. Some trees are butterflies.

1. A and B only
2. C and E only
3. B and E only
4. B and D only
सभी फूल खिलौने हैं। कुछ खिलौने पेड़ हैं। कुछ तितलियाँ पेड़ हैं, तब
A. कोई बटरफ्लाई फूल नहीं है।
B. कुछ तितलियाँ खिलौने हैं।
C. कुछ खिलौने फूल हैं।
D. कुछ पेड़ फूल हैं।
E. कुछ पेड़ तितलियाँ हैं।

SHOW ANSWER
  Answer 2
Explanation: In syllogism one must understand distributed and undistributed basics.
Here, from all positive, negative cannot come.
If we see all middle terms are undistributed so they cannot come and conclusions cannot be made through mediation.
So using only immediate (C) is correct as A converse is I from the first statement.
(E) is correct as I converse is I from last statement.
©navclasses




6. Find the odd one out among the following:


1. DfGj
2. HkLo
3. MoPs
4. TvWz
निम्नलिखित में से विषम का पता लगाएं:

SHOW ANSWER
  Answer 2
Explanation: Others have 1 gap, 2nd has 2 gaps.
©navclasses




7. In a coded language if ANIMAL is written as LAIMNA, then CIRCLE will be written as:


1. ELRCIC
2. ELCRIC
3. ERLCIC
4. ERCLIC
एक कूट भाषा में यदि ANIMAL को LAIMNA लिखा जाता है, तो CIRCLE को इस प्रकार लिखा जाएगा:

SHOW ANSWER
  Answer 1
Explanation: It is just crossed as A goes to the end and the last L comes in front.
©navclasses




8. Match list I with list II.

Typical Aristotelian syllogism Technical names in Nyaya philosophy
A. Socrates is mortal I. Nigamana
B. Because he is a man II. Upanaya
C. Whoever is a man, is a mortal e.g. Pythagoras III. Udaharan
D. Socrates is a man who is invariably a mortal IV. Hetu
E. Therefore Socrates is mortal V. Pratijna
Choose the correct answer from the options given below:

1. A -V, B – IV, C-III, D-II, E-I
2. A-I, B- II, C – III, D-IV, E-V
3. A – III, B – I, C – II, D-V, E – IV
4. A-II, B – III, C-I, D-IV, E-V
सूची I को सूची II के साथ सुमेलित करें।
विशिष्ट अरिस्टोटेलियन न्यायशास्त्र न्याय दर्शन में तकनीकी नाम
A. सुकरात नश्वर है I. निगमन
B. क्योंकि वह एक आदमी है II। उपनया
C. जो कोई भी मनुष्य है, वह नश्वर है उदा। पाइथागोरस III. उदाहारन
D. सुकरात एक ऐसा व्यक्ति है जो निरपवाद रूप से नश्वर है IV। हेतु
ई. इसलिए सुकरात नश्वर है वी. प्रतिज्ञा
नीचे दिए गए विकल्पों में से सही उत्तर चुनें:

SHOW ANSWER
  Answer 1
Explanation: It is as per Anuman sequence PHUUN
1. Socrates is mortal (called Pratijñā, required to be proved).
2. Because he is a man (called Hetu, reason, Sadhana).
3. Whoever is a man, is a mortal, e.g. Pythagoras (called Udaharana, i.e., the “example”).
4. Socrates is a man who is invariably a mortal (called Upanaya, reaffirmation).
5. Therefore Socrates is mortal (called Nigamana, conclusion).
©navclasses




9. What type of fallacy is implied in the following:

Fire is cold, because it is a substance.

1. Badhita
2. Virudha
3. Asādharna
4. Anup Samhan
निम्नलिखित में किस प्रकार की भ्रांति निहित है:
आग ठंडी है, क्योंकि यह एक पदार्थ है।

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  Answer 1
Explanation: Fire is cold, because it is a substance non-inferentially contradicted middle as there is no need to derive from reason from other or prior knowledge we know that Fire is hot not cold, it is Badhita
©navclasses




10. All knowable objects are nameable;

The pot is a knowable object; therefore, the pot is nameable.
The above is an example of which type of inference?

1. Kevalānvayi
2. Kevalavyātireki
3. Anvaya Vyatireki
4. Sheşavat
सभी जानने योग्य वस्तुएं नामी हैं;
बर्तन एक जानने योग्य वस्तु है; इसलिए, बर्तन नाम योग्य है।
उपरोक्त किस प्रकार के अनुमान का उदाहरण है?

SHOW ANSWER
  Answer 1
Explanation: Kevalānvayi: When the middle term is only positively related to the major term.
Kevalyātireki: When the middle term is only negatively related to the major term.
Anvaya Vyatireki: When the middle term is both positively and negatively related to the major term.
©navclasses

 

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